Jawab:
[tex]\rm Luas~~kawat~~kasar=\sf20\frac{3}{35}~~m^2[/tex]
Penjelasan dengan langkah-langkah:
Diketahui persegi panjang
Panjang (P) = [tex]5\frac{2}{7}~~m[/tex]
Lebar (L) = [tex]3\frac{4}{5}~~m[/tex]
Ditanya luas persegi panjang
Luas = P × L
[tex]Luas = (5\frac{2}{7})\times(3\frac{4}{5})~~m^2\\\\Luas = (5+\frac{2}{7})\times(3+\frac{4}{5})~~m^2\\\\Luas = (5\times3)+(5\times\frac{4}{5})+(\frac{2}{7}\times3)+(\frac{2}{7}\times\frac{4}{5})~~m^2\\\\Luas = 15+4+(\frac{6}{7}+\frac{8}{35})~~m^2\\\\Luas = 15+4+(\frac{6\times5}{7\times5}+\frac{8}{35})~~m^2\\\\Luas = 15+4+(\frac{30}{35}+\frac{8}{35})~~m^2\\\\Luas = (15+4+\frac{35}{35})+\frac{3}{35}~~m^2\\\\Luas = (15+4+1)+\frac{3}{35}~~m^2\\\\Luas = 20+\frac{3}{35}~~m^2[/tex]
[tex]\rm Luas=20\frac{3}{35}~~m^2[/tex]
( x c v i )
[answer.2.content]